FAQ (Frequently Asked Questions)
Operation of standard-controllers at high voltages: Series Connection
Figure 1: Series Connection
When controllers are connected in a series, neither the load output nor the module inputs are allowed to connect in a series, so that the controller is not damaged. When more systems are connected in a series, the total voltage can exceed the safety low voltage level. The single controller is not intended for use in this range and does therefore not correspond to the insulation requirements for DC-voltages higher than75V. When the controller is installed, pay attention that open-lying lines in which more than 50V are applied must be sufficiently insulated. The load disconnection can be used in 48V systems, Steca does however does not take any guarantee for this connection. In the worst case i. e. load disconnection at overvoltage, a voltage of 60V is applied on the FET of controller 2. As the max. admissabledra in-source can only be 55V, no advise for installation is given. As a rule, the load is disconnected because of overdischarge. Thus the FET cut-off voltage is smaller than 45V. When the FET is conducting, the voltage applied is smaller than1V.
Operation of standard controllers at high currents: Parallel Connection
In a parallel connection neither the load outputs nor the module inputs are allowed to be connected parallel, so that the controller is not damaged. As in single operation, all plus lines can be connected with each other and earthed.
Figure 2: Parallel Connection
The load outputs must not be switched in parallel, as the controllers do not disconnect at the same time and thus the whole load current flows over the FET, which is still conducting. You can also download this Application Note.
1. What is a DC-AC inverter?
The utility grid supplies you with alternating current (AC) electricity. AC is the standard form of electricity for anything that "plugs in" to the utility power. Direct current (DC) electricity flows in a single direction. Batteries provide DC electricity. AC alternates its direction many times per second. AC is used for grid service because it is more practical for long distance transmission.
An inverter converts DC to AC, and also changes the voltage. In other words, it is a power adapter. It allows a battery-based system to run conventional AC appliances directly or through conventional home wiring. There are ways to use DC directly, but for a modern lifestyle, you will need an inverter for the vast majority, if not all of your loads (in electrical terms, "loads" are devices that use electrical energy).
Incidentally, there is another type of inverter called grid-interactive. It is used to feed solar (or other renewable) energy into a grid-connected home and to feed excess energy back into the utility grid. This inverter is NOT grid interactive
2. What are the criteria for selecting the right inverter for a particular application?
To choose an inverter; you should first define your needs. Where is the inverter to be used? Inverters are available for use in buildings (including homes), for recreational vehicles, boats, and portable applications. Will it be connected to the utility grid in some way? Electrical conventions and safety standards differ for various applications, so don't improvise.
3. What are the electrical standards pertaining to DC-AC inverters?
The DC input voltage must conform to that of the electrical system and battery bank. 12 volts is recommended for small, simple systems. 24 and 48 volts are the common standards for higher capacities. A higher voltage system carries less current, which makes the system wiring cheaper and easier.
The inverter's AC output must conform to the conventional power in the region in order to run locally available appliances. The standard for AC utility service in North America is 120 and 240 Volts at a frequency of 60 Hertz (cycles per second). In Europe, South America, and most other places, it is 230 volts at 50 Hertz.
4. What are "continuous" and "surge" power capacity ratings for DC-AC inverters?
How much load can an inverter handle? Its power output is rated in Watts. Read details under "Characteristics of Sinusoidal AC Power" on page 7. There are two levels of power rating -a continuous rating and a surge rating. Continuous means the amount of power the inverter can handle for an indefinite period of hours. When an inverter is rated at a certain number of Watts, that number generally refers to its continuous rating. The "surge power" indicates the power to handle instantaneous overload of a few seconds to provide the higher power required to start certain type of devices and appliances.
5. What types of electrical loads require "surge power"?
Resistive types of loads (like incandescent lamps, toaster, coffee maker, electric range, iron etc) do not require extra power to start. Their starting power is the same as their running power.
Some loads like induction motors and high inertia motor driven devices will initially require a very large starting or "surge" power to start from rest. Once they have started moving and have attained their rated speed, their power requirement reduces to their normal running power. The surge may last up to 5 seconds. TVs and microwave ovens also require surge power for starting. The manufacturers' specification of the appliances and devices indicates only the running power required. The surge power required has to be guessed at best. See below under "Sizing of inverter for loads that require starting surge"
6. How do "surge power" electrical loads affect DC-AC inverter operation?
If an inverter cannot efficiently feed the surge power, it may simply shut down instead of starting the device. If the inverter's surge capacity is marginal, its output voltage will dip during the surge. This can cause a dimming of the lights in the house, and will sometimes crash a computer.
Any weakness in the battery and cabling to the inverter will further limit its ability to start a motor. A battery bank that is undersized, in poor condition, or has corroded connections, can be a weak link in the power chain. The inverter cables and the battery interconnect cables must be sized properly. The spike of DC current through these cables is many hundreds of amps at the instant of motor starting.
7. How should I size my DC-AC inverter for loads that require starting surge?
Observe the following guideline to determine the continuous wattage of the inverter for powering loads that require starting surge. (Multiply the running watts of the device/appliance by the Surge Factor)
NOTE: The surge power rating specified for this inverter is valid for duration of less than 1 second. This very short duration may not be sufficient to start motor based loads which may require up to 5 seconds to complete starting process. Hence, for purposes of sizing the inverter, use only the continuous power rating of this inverter.
|Type of Device or Appliance|| Surge Factor
(No. of times the running power rating of the device/appliance)
|Refrigerator / Freezer||5|
|Portable diesel / kerosene fuel heater||2|
8. How should I size my DC-AC inverter to operate a microwave?
The power rating of the microwave generally refers to the cooking power. The electrical power consumed by the microwave will be approximately 2 times the cooking power. The "surge power" of the inverter should be 2 times the electrical power (i.e., 4 times the cooking power). Please note that the surge power of the microwave is not as long as the motor load and hence, the surge power of the inverter can be considered to determine adequacy of meeting the starting surge power
9. How should I size my DC-AC inverter to power a water supply pump?
A water well or pressure pump often places the greatest demand on the inverter. It warrants special consideration. Most pumps draw a very high surge of current during start up. The inverter must have sufficient surge capacity to handle it while running any other loads that may be on. It is important to size an inverter sufficiently, especially to handle the starting surge (If the exact starting rating is not available, the starting surge can be taken as 3 times the normal running rating of the pump). Oversize it still further if you want it to start the pump without causing lights to dim or blink.
In North America, most pumps (especially submersibles) run on 240 VAC, while smaller appliances and lights use 120 VAC. To obtain 240 VAC from a 120 VAC inverter, use a 120 VAC to 240 VAC transformer. If you do not already have a pump installed, you can get a 120 volt pump if you don't need more than 1/2 HP.
10. What is "idle power" in a DC-AC inverter?
Idle power is the consumption of the inverter when it is on, but no loads are running. It is "wasted" power, so if you expect the inverter to be on for many hours during which there is very little load (as in most residential situations), you want this to be as low as possible.
11. What are Phantom and idling loads?
Most of the modern gadgets draw some power whenever they are plugged in. Some of them use power to do nothing at all. An example is a TV with a remote control. Its electric eye system is on day and night, watching for your signal to turn the screen on. Every appliance with an external wall-plug transformer uses power even when the appliance is turned off. These little loads are called "phantom loads" because their power draw is unexpected, unseen, and easily forgotten.
A similar concern is "idling loads." These are devices that must be on all the time in order to function when needed. These include smoke detectors, alarm systems, motion detector lights, fax machines, and answering machines. Central heating systems have a transformer in their thermostat circuit that stays on all the time. Cordless (rechargeable) appliances draw power even after their batteries reach a full charge. If in doubt, feel the device. If it's warm, that indicates wasted energy.
12. Can a standard DC-AC inverter be connected in parallel with another AC source/ DC-AC inverter / electrical utility?
The AC output of standard inverters cannot be synchronised with another AC source and hence, it is not suitable for paralleling. The AC output of the inverter should never be connected directly to an electrical breaker panel / load center which is also fed from the utility power /generator. Such a connection may result in parallel operation of the different power sources and AC power from the utility / generator will be fed back into the inverter which will instantly damage the output section of the inverter and may also pose a fire and safety hazard. If an electrical breaker panel / load center is fed from an inverter and this panel is also required to be powered from additional alternate AC sources, the AC power from all the AC sources like the utility / generator / inverter should first be fed to a manual selector switch and the output of the selector switch should be connected to the electrical breaker panel / load center. To prevent possibility of paralleling and severe damage to the inverter, never use a simple jumper cable with a male plug on both ends to connect the AC output of the inverter to a handy wall receptacle in the home / RV.
13. How can DC-AC inverters be connected to multi-wire branch circuits?
Do not directly connect the hot side of the inverter to the two hot legs of the 120 / 240 VAC electrical breaker panel / load centre where multi-wire ( common neutral ) branch circuit wiring method is used for distribution of AC power. This may lead to overloading / overheating of the neutral conductor and is a risk of fire. A split phase transformer (isolated or auto-transformer ) of suitable wattage rating ( 25 % more than the wattage rating of the inverter ) with primary of 120 VAC and secondary of 120 / 240 VAC ( Two 120 VAC split phases 180 degrees apart) should be used. The hot and neutral of the 120 VAC output of the inverter should be fed to the primary of this transformer and the 2 hot outputs ( 120 VAC split phases ) and the neutral from the secondary of this transformer should be connected to the electrical breaker panel / load centre.
14. How should I size my DC-AC inverter to supply computer or printer loads?
Computers and Printers generally come with in-built switch-mode power supplies (seeÂ FAQs on switch mode power supplies (SMPS)) that have extremely low power factor on account of the extremely peaky and non-linear nature of the current drawn by them from the AC source. Hence for such loads we recommend using inverters with three times the advertised power consumption of the computer or printer loads.
15. What is the difference between a 12V, 24V and 48V inverter?
A 12-V can be fed from a 12V battery or DC supply. Similarly 24V and 48V inverters can be fed from 24V and 48V batteries/DC power supplies respectively. Cars usually have 12V batteries. Trucks have 24V batteries.
1. What is sinusoidal AC voltage (i.e. voltage with a sine-waveform)?
The voltage waveform of 120 VAC, 60 Hz mains / utility power is like a sine wave. In a voltage with a sine wave-form, the instantaneous value and polarity of the voltage varies with respect to time and the wave-form is like a sine wave. In one cycle, it slowly rises in the positive direction from 0 V to a peak positive value + Vpeak = 170 V, slowly drops to 0 V, changes the polarity to negative direction and slowly increases in the negative direction to a peak negative value - Vpeak =170 V and then slowly drops back to 0 V. There are 60 such cycles in 1 sec.
2. What is frequency of a sine-wave?
The number of sine-wave cycles per second is called the "frequency" and is also termed "Hertz (Hz.)".
3. What is Power Factor?
If a linear load is connected to this type of voltage, the load will draw current which will also have the same sine wave-form. However, the peak value of the current will depend upon the impedance of the load. Also, the phase of the sine wave-form of the current drawn by the linear load may be the same or lead / lag the phase of sine wave-form of the voltage. This phas difference determines the "Power Factor (mathematically = the cosine of the phase difference)" of the load.
4. What is the Power factor for a resistive type of load?
In a resistive type of load (like incandescent lamps, heaters etc) the sine wave-form of the current drawn by the load has 0 phase difference with the sine wave-form of the voltage of the AC power source. The Power Factor of a resistive load is unity (1). The rated output power (in Watts) of the inverters is normally specified for resistive type of loads that have unity (1) Power Factor.
5. What is the Power factor for a reactive type of load?
In a reactive type of load (like electric motor driven loads, fluorescent lights, computers, audio / video equipment etc), the phase of the sine wave-form of the current drawn by the load may lead or lag the sine wave-form of the AC voltage source. In this case, the power factor of reactive loads is lower than unity (1) â€“ generally between 0.8 and 0.6. A reactive load reduces the effective wattage that can be delivered by an AC power source
6. What are RMS and peak values of a sinusoidal AC voltage source?
As explained above, in a sine wave, the instantaneous values of AC voltage (Volt, V) and current (Ampere, A) vary with time. Two values are commonly used â€“ Root Mean Square (RMS) value and peak value. For simplicity, RMS value can be considered as an average value. Mathematically, Peak Value = 1.414 x RMS value. For example, the 120 VAC, 60 Hz. mains / utility power is the RMS value. The peak value corresponding to this is = 1.414 x 120 = 170V.
The values of the rated output voltage and current of an AC power source are their RMS values
7. How is the Power of an AC source specified?
The power rating of an AC power source is designated in Volt Amperes (VA) or in Watts (W)
Power in Volt Amperes (VA) = RMS Volts (V) x RMS Amps (A)
Power in Watts = RMS Volts (V) x RMS Amps (A) x Power Factor
8. What does the specified rated Power of a DC-AC inverter signify?
The rated power of the inverter in Watts (W) is normally designated for a linear, resistive type of load that draws linear current at unity (1) power factor. If the load is linear and reactive type, the rated power of the inverter in watts will be limited to its normal rated power in watts (W) x Power Factor. For example, an inverter rated for 1000 W ( at unity power factor) will be able to deliver only 600 watts to a reactive type of load with a power factor of 0.6
1. What is the nature of current drawn by Switch Mode Power Supplies (SMPS)?
Power supplies are used to convert AC voltages like 120 VAC to various DC voltages like 3.3 V, 5 V, 12 V, 24 V, 48 V etc. Majority of modern day electronic devices use embedded general purpose Switch Mode type of Power Supplies (SMPS) to drive the electronic circuitry. General purpose Switch Mode Power Supplies (SMPS) (excepting those that have power factor correction) have one major disadvantage â€“ the current drawn by them from the AC power source has a non linear waveform - the waveform is not sinusoidal as the input voltage waveform but is in the form of short, larger value pulses around the area of + Vpeak and -Vpeak. This is due to the charging of the input filter capacitor(s) mostly around the positive and negative peak portions of the sinusoidal input voltage.
2. What is crest factor?
The degree of non-linearity is measured by the "Crest Factor": Crest Factor = Peak Current / RMS Current
In a linear load, the Crest Factor is 1.414. However, in a general purpose SMPS, due to its non linear nature, this factor will be much higher - in the region of up to 4. This will mean that for a particular rated RMS current (applicable for a linear load), the general purpose SMPS will draw much larger peak currents â€“ approx. up to 4 times more than its rated RMS current.
3. Why does a DC/AC inverter prematurely shut down while supplying power to a general purpose Switch Mode Power Supply (SMPS)?
Inverters are protected against over current ( also called overloading ) by either clipping the peaks of the output voltage ( this will result in a sine wave becoming a square wave, reduction in the RMS value of the output voltage and generation of harmonics and electrical noise ) or by shutting down the output voltage of the inverter completely. Thus, if an inverter / generator is used to power a general purpose SMPS, it will be forced to deliver higher peak currents resulting in premature triggering of the inverter's / generator's over current protection circuits.
4. How should my DC/AC Inverter be sized to operate a general purpose Switch Mode Power Supply (SMPS)?
For safe operation, the continuous RMS current rating of the inverter / generator should be at least 2.8 times the continuous RMS current rating of the general purpose SMPS it is required to power:
Peak current of inverter = Peak current of SMPS
RMS current of inverter X 1.414 = RMS current of SMPS X 4
RMS current of inverter = 4/1.414 X RMS current of SMPS
RMS current of inverter = 2.8 X RMS current of SMPS
Alternatively, the continuous power rating of the inverter / generator in Watts / VA should be at least 2.8 times the continuous power rating of the SMPS in Watts / VA
1. What is the conductor configuration for single phase AC Power transmission?
For single phase transmission of AC power or DC power, two conductors are required that will be carrying the current. These are called the "current-carrying" conductors. A third conductor is used for grounding to prevent the build up of voltages that may result in undue hazards to the connected equipment or persons. This is called the "non current-carrying" conductor (will carry current only under ground fault conditions)
2. What does the term "grounded" indicate?
The term "grounded" indicates that one or more parts of the electrical system are connected to earth, which is considered to have zero voltage or potential. In some areas, the term "earthing" is used instead of grounding.
3. What is a "grounded conductor"?
A "grounded conductor" is a "current-carrying" conductor that normally carries current and is also connected to earth. Examples are the "neutral" conductor in AC wiring and the negative conductor in many DC systems. A "grounded system" is a system in which one of the current-carrying conductors is grounded.
4. What is an "equipment grounding conductor"?
An "equipment grounding conductor" is a conductor that does not normally carry current (except under fault conditions) and is also connected to earth. It is used to connect the exposed metal surfaces of electrical equipment together and then to ground. Examples are the bare copper conductor in non-metallic sheathed cable (Romex Â®) and the green, insulated conductor in power cords in portable equipment. These equipment-grounding conductors help to prevent electric shock and allow over-current devices to operate properly when ground faults occur. The size of this conductor should be coordinated with the size of the over-current devices involved
5. What is a "grounding electrode"?
A "grounding electrode" is the metallic device that is used to make actual contact with the earth. Other types of grounding electrodes include metal water pipes and metal building frames.
6. What is a "grounding electrode conductor"?
A "grounding electrode conductor" is the conductor between a common single grounding point in the system and the grounding electrode
7. What does a "Bond" refer to?
"Bond" refers to the connection between the "grounded conductor", the "equipment grounding" conductors and the "grounding electrode" conductor. Bonding is also used to describe connecting all of the exposed metal surfaces together to complete the equipment-grounding conductors.
8. What does a "grounded electrical power distribution system" refer to?
The National Electrical Code (NEC) requires the use of a "grounded electrical distribution system" for a permanently connected AC power source. As per this system, one of the two current-carrying conductors is required to be grounded. This grounded conductor is called the "Neutral / Cold / Return". As this conductor is bonded to earth ground, it will be at near zero voltage or potential. There is no risk of electrical shock if this conductor is touched. The other current carrying conductor is called the "Line / Live / Hot". The connection between the "Neutral" and the grounding electrode conductor is made only at one point in the system. This is known as the system ground. This single point connection (bond) is usually made in the service entrance or in the load center. If this connection is inadvertently made in more than one place, then unwanted currents will flow in the equipment grounding conductors. These unwanted currents may cause inverters and charge controllers to be unreliable and may interfere with the operation of ground-fault detectors and over-current devices
NOTE: In a single phase AC power source, a current-carrying conductor that is not bonded to the earth ground cannot be called a "neutral". This conductor will be at an elevated voltage with respect to the earth ground and may produce electrical shock when touched.
9. What is the polarity and color codes for power cords, plugs and receptacles used with 120 V, 60 Hz electrical systems?
Single phase 120 VAC, 60 Hz AC devices and appliances use 2 pole, 3 wire grounding configuration for making AC side connections. The plug / receptacle has three pins / slots â€“ two flat pins / slots (also called poles) that are connected to the two current-carrying conductors and a round pin / slot which is connected to a non-current carrying conductor (this will carry current only during ground fault conditions) One flat pin / slot is connected to a black current-carrying conductor which is also called "Line/Live/Hot" pole. The other flat pin / slot is connected to the white current-carrying conductor also called the "Neutral / Return / Cold" pole. The third round pin / slot is connected to the non-current carrying green "equipment grounding conductor". This green "equipment grounding conductor" is bonded to the metal chassis of the device or appliance. The plug (for example 15 A, NEMA5-15P) will mate with the corresponding female slots of the NEMA 5-15R receptacle
10. What precaution should be taken in inverters where none of the current carrying conductors is bonded to the chassis?
In some inverters designed for portable use, the two current carrying conductors connected to the "Line/Live/Hot" slot and the "Neutral / Return / Cold" slot of the receptacle ( for example, 15 A NEMA5-15R) are isolated from the metal chassis of the inverter. In these inverters, none of the two poles can be called Neutral as both these poles are isolated from the chassis of the inverter. Both the Line and Neutral slots of the receptacle will be at an elevated voltage with respect to the chassis â€“ normally around 60 VAC (Half of the voltage between the two current carrying conductors). Hence, do not touch the neutral slot of the receptacle!
These types of inverters are designed to be connected directly to the AC loads. These are not designed to be permanently installed into household or recreational vehicle AC distribution wiring. As this type of connection / installation can not be classified as a permanent installation, the NEC requirement of grounded distribution system doesn't strictly apply.
11. What are the standards pertaining to inverters where none of the current carrying conductors is bonded to the chassis?
The UL standard for this type of inverters- UL458 does not have a requirement for a bonded neutral on the output of inverters. As long as the installation requirement of grounding the chassis of the inverter has been accomplished, loads that are plugged in will have their chassis held at the same ground potential as the chassis of the inverter and the house or RV. The only difference is that the neutral slot of the receptacle has approximately 60V on it instead of the usual 0V.Â The impact of thisÂ is minimal, since parts of wiring and equipment that are connected to the neutral side of the circuit are required by safety standards to be treated as if they were at 120VAC, since there are many receptacles that are wired backwards or 2-prong plugs that are not polarized.Â Therefore, a voltage of approximately 60VAC of the Neutral slot is not accessible to the user, and any shock hazard presented is mitigated by lack of access.Â The main safety agencies, CSA, UL, and ETL, have all approved inverters with this half-voltage on the neutral scheme.
|1. What is the cause of Electromagnetic Interference (EMI) in inverters?
2. What are the factors governing EMI generation?
3. How can the effects of EMI be reduced or eliminated?
1. What is the cause of Electromagnetic Interference (EMI) in inverters?
The inverter contains internal switching devices which generate conducted and radiated electromagnetic interference (EMI).
2. What are the factors governing EMI generation?
The effects of EMI will also depend upon a number of factors external to the power supply like proximity of the inverter to the EMI receptors, types and quality of connecting wires and cables etc.
3. How can the effects of EMI be reduced or eliminated?
The magnitude of EMI is limited to acceptable levels by circuit design but can not be entirely eliminated.
EMI due to factors external to the inverter can be reduced as follows:
- Ensure that the inverter is firmly grounded to the ground system of the building or the vehicle
- Locate the inverter as far away from the EMI receptors like radio, audio and video devices as possible
- Keep the DC side cables between the battery and the inverter as short as possible
- Twist the DC side cables. This will partially cancel out the radiated noise from the cables
- Shield the DC side cables with metal sheathing / copper foil / braiding
- Use co-axial shielded cable for all antenna inputs (instead of 300 ohm twin leads)
- Use high quality shielded cables to attach audio and video devices to one another
- Do not operate other high power loads when operating audio / video equipment
|1. What is a Pure Sine-wave Inverter?
2. What is a Modified Sine-wave Inverter?
3. What are the advantages of Pure Sine-wave inverters?
4. Which devices will not function properly from a Modified Sine-wave Inverter?
1. What is a Pure Sine-wave Inverter?
The output voltage of a sine-wave inverter has a sine wave-form like the sine wave-form of the mains / utility voltage. In a sine wave, the voltage rises and falls smoothly with a smoothly changing phase angle and also changes its polarity instantly when it crosses 0 Volts.
2. What is a Modified Sine-wave Inverter?
In a modified sine wave, the voltage rises and falls abruptly, the phase angle also changes abruptly and it sits at 0 Volts for some time before changing its polarity.
3. What are the advantages of Pure Sine-wave inverters?
- The output wave-form is a sine-wave with very low harmonic distortion and clean power like utility supplied electricity
- Inductive loads like microwaves and motors run faster, quieter and cooler
- Reduces audible and electrical noise in fans, fluorescent lights, audio amplifiers, TV, fax and answering machines
- Prevents crashes in computers, weird print outs and glitches in monitors
4. Which devices will not function properly from a Modified Sine-wave Inverter?
Any device that uses a control circuitry that senses the phase (for voltage / speed control) or instantaneous zero voltage crossing (for timing control) will not work properly from a voltage that has a modified sine wave-form. Also, as the modified sine wave is a form of square wave, it is comprised of multiple sine waves of odd harmonics (multiples) of the fundamental frequency of the modified sine wave. For example, a 60 Hz. modified sine wave will consist of sine waves with odd harmonic frequencies of 3rd (180 Hz), 5th (300 Hz.), 7th (420 Hz.) and so on. The high frequency harmonic content in a modified sine wave produces enhanced radio interference, higher heating effect in motors / microwaves and produces overloading due to lowering of the impedance of low frequency filter capacitors / power factor improvement capacitors.
Some examples of devices that may not work properly with modified sine wave and may also get damaged are given below
- Laser printers, photocopiers, magneto-optical hard drives
- The built-in clocks in devices such as clock radios, alarm clocks, coffee makers, bread-makers, VCR, microwave ovens etc may not keep time correctly
- Output voltage control devices like dimmers, ceiling fan / motor speed control may not work properly (dimming / speed control may not function)
- Sewing machines with speed / microprocessor control
- Transformer-less capacitive input powered devices like (i) Razors, flashlights, night-lights, smoke detectors etc (ii) Re-chargers for battery packs used in hand power tools. These may get damaged. Please check with the manufacturer of these types of devices for suitability
- Devices that use radio frequency signals carried by the AC distribution wiring
- Some new furnaces with microprocessor control / Oil burner primary controls
- High intensity discharge (HID) lamps like Metal Halide lamps. These may get damaged. Please check with the manufacturer of these types of devices for suitability
- Some fluorescent lamps / light fixtures that have power factor correction capacitors. The inverter may shut down indicating overload
1. What is a step-up DC-DC converter?
A step-up dc-dc converter is an electronic circuit that raises the DC voltage level from a lower value to a higher value. Assuming an ideal converter (100% efficiency),
Input Power = Output Power
Input Voltage Ã— Input Current = Output voltage Ã— Output current.
Hence a step-up dc-dc converter will reduce the input current level to a lower value at the output in the same proportion that it raises the value of the input voltage.
Step-up dc-dc converters would typically find applications in RV vehicles, heavy trucks, buses, marine vehicles, Land mobile radios, CB radios, lighting systems, AM/FM sound systems.
2. What is a step-down DC-DC converter?
A step-up dc-dc converter is an electronic circuit that lowers the DC voltage level from a higher value to a lower value. Assuming an ideal converter (100% efficiency),
Input Power = Output Power
Input voltage Ã— Input current = Output voltage Ã— Output current.
Thus, a step-down dc-dc converter will increase the input current level to a higher value at the output in the same proportion that it lowers the value of the input voltage.
Step-up dc-dc converters would typically find applications in Earth-moving equipment, heavy trucks, buses, marine vehicles, CB radios, lighting systems, AM/FM sound systems.
3. What is the difference between isolated and non-isolated DC-DC converters?
Isolated dc-dc converters provide full dielectric isolation (no electric contact) between input and output circuits by means of a high frequency transformer, which may be a requirement by certain safety agencies or for certain applications.
Typical applications requiring isolated dc-dc converters would be Communications, Forklifts etc.
4. What are the advantages of isolated DC-DC converters?
- Safety to personnel, isolation prevents input voltage from transmitting to the output in case of internal failure.
- Isolated DC-DC converters can be configured to provide positive or negative outputs from plus or minus rails.
- Voltage transients on the input are not transmitted to the output.
5. How can isolated DC-DC converters be configured to provide positive or negative outputs from plus or minus rails?
Isolated DC-DC voltage converters can provide positive or negative voltages from a single device. Most isolated converters have "floating" outputs that provide isolation between the case, the input and the output circuitry (See Fig.1A & B).
Figure 1a: Isolation between case, input and output circultry
Figure 1b: Simplified input/output circultry for single output device
Connecting the output circuit reference node (ground) to the positive output will cause the output common of the device to be at a relative negative voltage. For example, by connecting the 12V output of the 12V output versions of SD or IDC series to ground, the output common may be used to supply a negative voltage (-12V) to the load. (See Fig. 2).
Figure 2: Isolated output configured to provide negative voltage
Isolated DC-DC converters may be also be used with either a positive or a negative input voltage source, as long as the relative polarity of the input to the device is maintained. (See Fig. 3)
Figure 3: Negative input voltage operation
The positive input (Vin) must be positive with respect to the input return. The input return must be kept negative with respect to the Vin pin. If this polarity is reversed, the converter input will approximate a forward biased diode and permanent damage to the unit will occur. An example of operating from a negative source is shown, connecting the input return to the â€“24V and the input positive terminal to ground, maintaining the correct polarity. The outputs can still be made either positive or negative as described earlier.
|1. What should be the rating of the output fuse on the IDC series isolated DC-DC converter?
2. What is the overload protection mechanism in the IDC-series isolated DC-DC converters?
1. What should be the rating of the output fuse on the IDC series isolated DC-DC converter?
The output fuse should have a current rating equal to the output current rating of the respective converter.
2. What is the overload protection mechanism in the IDC-series isolated DC-DC converters?
The IDC-series isolated DC-DC converters have a fold-back current limiting mechanism, where-in as the load current increases above the rated value, the output voltage drops and automatically resets to the original voltage value once the overload is removed.
1. Can the SDC-series dc-dc converter be used directly to charge batteries?
The SDC-series dc-dc converter cannot be directly used to charge batteries as the battery will feed back into SDC-series dc-dc converter if the input to SDC-series converter is removed or if there is no output from SDC-series dc-dc converter due to any reason. This will damage SDC-series dc-dc converter. In addition, if the 12V battery is deeply discharged, it will send SDC-series converter into current limit for extended period of time and will lead to premature failure.
2. How can the SDC-series dc-dc converter be modified to work as a battery charger?
A Schottky diode (rated at 30 V, 30 A) in series with the positive output of SDC-series converter will eliminate feed back into SDC-series dc-dc converter. To compensate for the drop across the Schottky diode (0.4V to 0.5 V), the output voltage of SDC-series dc-dc converter should be increased to around 14V to provide a float voltage of 13.5 V for charging a 12 V battery (The output voltage of SDC-series converter can be adjusted using the internal output voltage control potentiometer (Call Tech Support for exact part reference). Premature failure can also be avoided by reducing the current limit with the help of internal potentiometer (Call Tech Support for exact part reference).
3. How can the BBM-1225 be used in conjunction with the SDC-series converter to function as a battery charger and DC UPS?
If it is desired to use the SDC-series dc-dc converter for battery charging, the battery back-up module BBM-1225 could be used in conjunction with SDC-series dc-dc converter. The Battery Terminal of the output of BBM-1225 will provide a charging current of around 4 A. The customer will have to adjust the output voltage of SDC-series dc-dc converter to 14 V as explained above when using BBM-1225. The customer will be able to power his 12 V load through the Load Terminal of the output of BBM-1225 up to the current rating of the respective SDC-series dc-dc converter less 4 amps.
|1. Can the output voltage on the SD-1000L-48 be varied?
2. What is the switching frequency of the SD-1000L-series converter?
1. Can the output voltage on the SD-1000L-48 be varied?
By means of an internal potentiometer the output voltage can be varied from 46 - 60 volts DC.
2. What is the switching frequency of the SD-1000L-series converter?
The SD-1000L-48 consists of a two-stage DC/DC converter. The first stage (Boost) has a switching frequency of 70 kHz. The second stage (isolation) has a switching frequency of 90 kHz. The two switching frequencies are different so that they don't superimpose emitting radiated and conducted EMI noise.
|1.The input circuit breaker to my VTC 605-12-24 trips every time I turn the converter on, even though the converter is not connected to full load?|
1.The input circuit breaker to my VTC 605-12-24 trips every time I turn the converter on, even though the converter is not connected to full load?
The input capacitors draw a high current initially to get charged at start-up. Make sure the circuit breaker rating is the same as that of the fuse on the input side. In the case of the VTC 605-12-24, this is 60 Amps.
- automotive service - Starting/Lighting/Ignition (SLI, a.k.a. cranking)
- deep cycle service
Everybody is familiar with the SLI batteries that are used for automotive starting and powering vehicular accessories. SLI batteries are designed to produce high power in short bursts but must be constantly recharged (normally with an alternator while driving). Vehicle starting typically discharges 1%-3% of a healthy SLI battery's capacity. The automotive SLI battery is not designed for repeated deep discharge where up to 80% of the battery capacity is discharged and then recharged. If an SLI battery is used for this type of application, its useful service life will be drastically reduced
3. What are Deep Cycle Batteries?
Deep cycle batteries are designed with thick-plate electrodes to serve as primary power sources, to have a constantdischarge rate, to have the capability to be deeply discharged up to 80 % capacity and to repeatedly accept recharging. They are marketed for use in recreation vehicles (RV), boats and electric golf carts â€“ so they may be referred to as RV batteries, marine batteries or golf cart batteries. There are two categories of deep cycle lead acid batteries â€“ wet and sealed. A wet cell battery has a high tolerance to overcharging. However, it will release hydrogen gas when charging that must be properly vented and the water level must be checked frequently. Sealed batteries can either be Gel Cell or AGM (Absorbed Glass Mat). Both the Gel Cell and AGM are maintenance free, have no liquid to spill and gassing is minimal. The Gel Cell is the least affected by temperature extremes, storage at low state of charge and has a low rate of self discharge. An AGM battery will handle overcharging slightly better than the Gel Cell
4. What are the Units of Battery capacity?
The battery capacity is the measure of the energy the battery can store and deliver to a load. It is determined by how much current any given battery can deliver over a stipulated period of time. The energy rating is expressed in Ampere Hours (AH). As a bench mark, the battery industry rates batteries at 20 hour rate i.e. how many Amperes of current the battery can deliver for 20 hours at 80 Âº F till the voltage drops to 10.5 Volts for 12 V battery and 21 V for 24 V battery. For example, a 100 AH battery will deliver 5 Amperes for 20 hours. Battery capacity is also expressed as Reserve Capacity (RC) in minutes. Reserve capacity is the time in minutes for which the battery can deliver 25 Amperes at 80 Âº F till the voltage drops to 10.5 Volts for 12 V battery and 21 V for 24 V battery. Approximate relationship between the two units is as follows:
Capacity in AH = Reserve Capacity in RC minutes x 0.6
5. What are the Typical sizes of batteries applicable for powering inverters?
Below is a chart of some battery sizes applicable for powering inverters
|BCI * Group||Battery Voltage, V||Battery AH|
|27 / 31||12||105|
* Battery Council International
** Golf Cart
6. What is the trend observed in usable battery capacity at higher discharge rates?
As stated above, the rated capacity of the battery in AH is applicable at a discharge rate of 20 Hours. As the discharge rate is increased, the usable capacity reduces due to "Peukert Effect". This relationship is not linear but is more or less according to the table below:
Table 1: Battery Capacity versus Rate of Discharge
|Hours of Discharge||Usable Capacity|
Using the above table will show that a 100 AH capacity battery will deliver 100% (i.e. full 100 AH) capacity if it is slowly discharged over 20 hours at the rate of 5 Amperes. However, if it is discharged at a rate of 50 Amperes then theoretically, it should provide 100 AH Ã· 50 = 2 hours. However, the Table above shows that for 2 hours discharge rate, the capacity is reduced to 50% i.e. 50 AH. Therefore, at 50 Ampere discharge rate the battery will actually last for 50 AHÃ·50 Amperes = 1 Hour
7. What is the relationship between Depth of discharge and battery life?
The more deeply a battery is discharged on each cycle, the shorter the battery life. Using more batteries than the minimum required will result in longer life for the battery bank. A typical cycle life chart is given at Table 2 below:
Table 2: Typical Cycle Life Chart
|Depth of Discharge
% of AH Capacity
It is recommended that the depth of discharge should be limited to 50%.
8. What happens to battery capacity at low temperatures?
Batteries lose capacity in low temperatures. At 32Âº F, a battery will deliver about 70 to 80% of its rated capacity at 80Âº F. If the air temperature near the battery bank is lower than 80Âº F, additional batteries will be needed to provide the same usable capacity. For very cold climates, an insulated / heated battery compartment is recommended.
9. How can two or more batteries be connected in Series? What is the total capacity of the system?
When two or more batteries are connected in series, their voltages add up but their AH capacity remains the same. For example, when two 12 V, 105 AH batteries are connected in series, it becomes a 24 V, 105 AH battery. (Positive of the first battery is the positive terminal of the series connection. The negative of the first battery is connected to the positive of the second battery. The negative of the second battery is the negative of the series connection)
10. How can two or more batteries be connected in Parallel? What is the capacity of the system?
When two or more batteries are connected in parallel, their voltages remain the same but their capacities add up. For example, if two 12 V, 105 AH batteries are connected in parallel, their voltage remains 12 V but their capacity becomes 105 Ã— 2 = 210 AH (Connect the positive terminal of the first battery to the positive terminal of the second battery. These paralleled common positive terminals become the positive terminal of the parallel combination. Connect the negative terminal of the first battery to the negative terminal of the second battery. These paralleled common negative terminals becomes the negative terminal of the parallel combination)
11. How should the inverter battery bank be sized?
One of the most frequently asked question is, "how long will the batteries last?'. This question cannot be answered without knowing the size of the battery system and the load on the inverter. Usually this question is turned around to ask "How long do you want your load to run?", and then specific calculation can be done to determine the proper battery bank size.
There are a few basic formulae and estimation rules that are used
Formula 1 - Power in Watts (W) = Voltage in Volts (V) x Current in Amperes (A)
Formula 2 - For an inverter running from a 12 V battery system, the DC current required from the 12 V batteries is the AC power delivered by the inverter to the load in Watts (W) divided by 10
For an inverter running from a 24 V battery system, the D.C. current required from the 24 V battery is equal to the A.C. power delivered by the inverter to the load in Watts (W) divided by 20
Formula 3 - Energy required from the battery = DC current to be delivered (A) x time in Hours (H)
The first step is to estimate the total AC watts (W) of load(s) and for how long the load(s) will operate in hours (H). The AC watts are normally indicated in the electrical nameplate for each appliance or equipment. In case AC watts (W) are not indicated, formula 1 given above may be used to calculate the AC watts by multiplying 120 VAC by the AC current in Amperes . The next step is to derive the DC current in Amperes (A) from the AC watts as per formulae 2 above. An example of this calculation for 12 V inverter is given below.
Let us say that the total AC Watts delivered by the inverter = 1000 W
Then, using formula 2 above, the DC current to be delivered by the 12 V batteries = 1000 W Ã·10 = 100 Amperes
Next, the energy required by the load in Ampere Hours (AH) is determined. For example, if the load is to operate for 3 hours then as per Formula 3 above:
Energy to be delivered by the 12 V batteries = 100 Amperes Ã— 3 Hours = 300 Ampere Hours (AH)
Now, the capacity of the batteries is determined based on the run time and the usable capacity. From Table 1 above, the usable capacity at 3 Hour discharge rate is 60%. Hence, the actual capacity of the 12 V batteries to deliver 300 AH will be equal to 300 AH Ã· 0.6 = 500 AH
And finally, the actual desired rated capacity of the batteries is determined based on the fact that normally only 80% of the capacity will be available with respect to the rated capacity due to non availability of ideal and optimum operating and charging conditions. So the final requirements will be equal to:
500 AH Ã·0.8 = 625 AH (note that the actual energy required by the load was 300 AH)
It will be seen from the above that the final rated capacity of the batteries is almost 2 times the energy required by the load in AH
Thus, as a thumb rule, the AH capacity of the batteries should be twice the energy required by the load in AH
For the above example, the 12 V batteries may be selected as follows:
- Use 6 Group 27/31, 12 V, 105 AH batteries in parallel to make up 630 AH, or
- Use 3 Group 8D, 12 V, 225 AH batteries in parallel to make up 675 AH
12. How can batteries be charged?
The batteries can be charged by using good quality AC powered battery charger or from alternative energy sources like solar panels, wind or hydro systems. Make sure an appropriate battery charge controller is used. It is recommended that the batteries may be charged at 10% to 13 % of the Ampere Hour capacity (20 hour discharge rate). Also, for complete charging (return of 100 % capacity ), it is recommended that a 3 stage charger may be used (Constant current bulk charging followed by constant voltage boost / absorption charging followed by constant voltage float charging ).
13. What kind of Batteries should be used to power inverters in vehicles/RVs?
It is recommended that for powering the inverter, one or more auxiliary deep cycle batteries should be used that are separate from the SLI batteries. The inverter should be powered from the deep cycle batteries.
14. How should the Batteries be charged in vehicles / RVs?
For charging the SLI and the auxiliary deep cycle batteries, the output from the alternator should be fed to these two sets of batteries through a battery isolator of appropriate capacity. The battery isolator is a device that will allow the alternator to charge the two sets of batteries when the engine is running. The isolator will allow the inverter to be operated from the auxiliary batteries and also prevent the SLI batteries from charging the auxiliary deep cycle batteries when the engine is not running. Battery isolators are available from auto / RV / marine parts suppliers.
15. What is rating of alternators in vehicles / RVs?
A majority of smaller vehicles have 40 to 105 Ampere alternator and RVs have 100 to 130 Ampere alternator.
16. What if the available alternator in the vehicle / RV is not adequate?
When in use, the alternators heat up and their output current capacity can drop by up to 25%. When heated up, their charging voltage may also not reach the desired absorption voltage and will result in return of only about 80% of the battery capacity. In case the current output of the standard alternator is not adequate to charge the two sets of batteries rapidly and fully to 100% of their capacity, use heavy duty alternator that can produce higher current and voltage required to charge multiple battery systems. These alternators are available with auto / RV parts suppliers.
17. Can two or more battery chargers be connected in series/parallel?
No. Our battery chargers are not designed to be connected in series/parallel.
1. Can the SEC battery charger charge a battery while it is being connected to the load?
Yes. The SEC battery charger in the loaded battery condition (refer to the manual for appropriate DIP switch setting) can be used to charge the battery while it is connected to a load. Under this condition the charger operates as a two-stage charger bypassing the absorption stage to prevent damage to the batteries.
2. Can the SEC battery chargers supply a DC load in the absence of a battery?
In the loaded battery condition (refer to the manual for appropriate DIP switch setting) the SEC battery charger can work as a DC power supply to feed a DC load in the absence of a battery.
3. Can the SEC battery chargers be used in positive ground systems?
Yes. The output section of the SEC battery chargers is isolated from the input and hence can be used in positive ground systems.
4. What happens if in the loaded battery condition the load draws more current than the battery charger can supply?
In such a situation the excess current is drawn from the battery. In the long run this could drain the batteries, if the batteries are not re-charged. Hence it is recommended to use a battery charger with capacity equal to the sum of the current rating of the load and the desired charging current for the battery.
5. What DIP switch setting should be used to charge multiple battery banks?
The DIP switch setting corresponding to the loaded battery condition (refer to the manual for appropriate DIP switch setting) should be used to charge multiple battery banks to prevent overcharging of any single bank.